Yes, it is important if your item will be used as a key in a dictionary, or HashSet<T>
, etc - since this is used (in the absence of a custom IEqualityComparer<T>
) to group items into buckets. If the hash-code for two items does not match, they may never be considered equal (Equals
will simply never be called).
The GetHashCode()
method should reflect the Equals
logic; the rules are:
Equals(...) == true
) then they must return the same value for GetHashCode()
GetHashCode()
is equal, it is not necessary for them to be the same; this is a collision, and Equals
will be called to see if it is a real equality or not.In this case, it looks like "return FooId;
" is a suitable GetHashCode()
implementation. If you are testing multiple properties, it is common to combine them using code like below, to reduce diagonal collisions (i.e. so that new Foo(3,5)
has a different hash-code to new Foo(5,3)
):
int hash =13;
hash =(hash *7)+ field1.GetHashCode();
hash =(hash *7)+ field2.GetHashCode();...return hash;
Oh - for convenience, you might also consider providing ==
and !=
operators when overriding Equals
and GetHashCode
.