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Solve the following and check with the answers given at the end. There are three set of Aptitude and Puzzle Questions given below see all
1.It
was calculated that 75 men could complete a piece of work in 20 days. When work
was scheduled to commence, it was found necessary to send 25 men to another
project. How much longer will it take to complete the work?
2.A
student divided a number by 2/3 when he required to multiply
by 3/2. Calculate the percentage of error in his result.
3.A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg. His gain is ...%.
4.A
software engineer has the capability of thinking 100 lines of code in five
minutes and can type 100 lines of code in 10 minutes. He takes a break for five
minutes after every ten minutes. How many lines of codes will he complete
typing after an hour?
5.A man
was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for ... days.
6.A
contractor agreeing to finish a work in 150 days,
employed 75 men each working 8 hours daily. After 90 days, only 2/7 of the work
was completed. Increasing the number of men by-- ________ each working now for
10 hours daily, the work can be completed in time.
7.what is a percent of b divided by b
percent of a?
(a)a (b)b (c)1 (d)10 (d)100
8.A man
bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20
% gain, he would not lose anything; but if he sold the horse at 5% loss and the
cart at 5% gain, he would lose Rs. 10 in the bargain.
The amount paid by him was Rs._____for the
horse and Rs_____for the cart.
9.A
tennis marker is trying to put together a team of four players for a tennis
tournament out of seven available. males - a, b and c;
females- m, n, o and p. All players are of equal ability and there must be at
least two males in the team. For a team of four, all players must be able to
play with each other under the following restrictions:
b
should not play with m,
c
should not play with p, and
a
should not play with o.
Which of the following statements
must be false?
1.
b and p cannot be selected together
2.
c and o cannot be selected together
3.
c and n cannot be selected
together.
10. Five farmers have 7, 9, 11, 13 & 14
apple trees, respectively in their orchards. Last year, each of them discovered
that every tree in their own orchard bore exactly the same number of apples.
Further, if the third farmer gives one apple to the first, and the fifth gives
three to each of the second and the fourth, they would all have exactly the
same number of apples. What were the yields per tree in the orchards of the
third and fourth farmers?
11.Five boys were climbing a hill. J was
following H. R was just ahead of G. K was between G & H. They were climbing
up in a column. Who was the second?
12-18 John is undecided which of the four novels to
buy. He is considering a spy
thriller, a Murder mystery, a Gothic romance and a science
fiction novel. The books are written by Rothko, Gorky, Burchfield and Hopper,
not necessary in that order, and published by Heron, Piegon,
Blueja and sparrow, not necessary in that order.
(1) The book by Rothko is
published by Sparrow.
(2) The Spy thriller is published
by Heron.
(3) The science fiction novel is by Burchfield and is not published by Blueja.
(4)The Gothic romance is by
Hopper.
15.Pigeon publishes ____________.
16.The novel by Gorky
________________.
17.John purchases books by the authors
whose names come first and third in alphabetical order. He does not buy the books
______.
18.On the basis of the first paragraph and
statement (2), (3) and (4) only, it is possible to deduce that
1.
Rothko wrote the murder mystery or the spy thriller
2.
Sparrow published the murder mystery or the spy
thriller
3.
The book by Burchfield is published by Sparrow.
19. If a light flashes every 6 seconds, how many times will it
flash in 3/4 of an hour?
20.If point P is on line segment AB, then which of the following is always true?
(1)
AP = PB(2) AP > PB(3) PB > AP(4) AB > AP(5) AB > AP + PB
21.All men are vertebrates. Some mammals are
vertebrates. Which of the following conclusions drawn from
the above statement is correct.
All men are mammals
All mammals are men
Some vertebrates are mammals.
None
22.Which of the following statements drawn from the given
statements are correct?
Given:
All watches sold
in that shop are of high standard. Some of the HMT watches are sold in that
shop.
a)
All watches of high standard were manufactured by HMT.
b)
Some of the HMT watches are of high standard.
c)
None of the HMT watches is of high standard.
d)
Some of the HMT watches of high standard are sold in
that shop.
23-27.
1.
Ashland is north of East Liverpool and west of
Coshocton.
2.
Bowling green is north
of Ashland and
west of Fredericktown.
3.
Dover is south and east
of Ashland.
4.
East Liverpool is north
of Fredericktown and east of Dover.
5.
Fredericktown is north of Dover
and west of Ashland.
6.
Coshocton is south of Fredericktown and west of Dover.
23.Which of the towns mentioned is furthest of the north – west
(a) Ashland (b) Bowling green(c) Coshocton (d) East Liverpool (e) Fredericktown
24.Which of the following must be both north and east of
Fredericktown?
(a)
Ashland(b)
Coshocton(c) East Liverpool
I
a only II b only III c only IV a & b V
a & c
25.Which of the following towns must be
situated both south and west of at least one other town?
A.
Ashland
only
B.
Ashland
and Fredericktown
C.
Dover
and Fredericktown
D.
Dover,
Coshocton and Fredericktown
E.
Coshocton, Dover and East Liverpool.
26.Which of the following statements, if
true, would make the information in the numbered statements more specific?
(a)
Coshocton is north of
(b)
East Liverpool is north
of Dover
(c)
Ashland is east of Bowling green.
(d)
Coshocton is east of Fredericktown
(e)
Bowling green
is north of Fredericktown
27.Which of the numbered statements gives
information that can be deduced from one or more of the other statements?
(A) 1(B) 2(C)
3(D) 4(E) 6
28.Eight friends Harsha,
Fakis, Balaji, Eswar, Dhinesh, Chandra, Geetha, and Ahmed are sitting in a circle facing the
center. Balaji is sitting between Geetha
and Dhinesh. Harsha is
third to the left of Balaji and second to the right
of Ahmed. Chandra is sitting between Ahmed and Geetha
and Balaji and Eshwar are
not sitting opposite to each other. Who is third to the left of Dhinesh?
29.If every alternative letter starting from
B of the English alphabet is written in small letter, rest all are written in
capital letters, how the month“ September” be written.
(1)SeptEMbEr(2)SEpTeMBEr(3)SeptembeR
(4)SepteMber
(5)None
of the above.
30.The length of the side of a square is
represented by x+2. The length of the side of an equilateral triangle is 2x. If the square and the equilateral triangle have equal perimeter,
then the value of x is _______.
31.It takes Mr. Karthik
y hours to complete typing a manuscript. After 2 hours, he was called away.
What fractional part of the assignment was left incomplete?
32.Which of the following is larger than
3/5?
(1) ½(2)39/50(3)7/25 (4)3/10 (5)59/100
33.The number that does not have a
reciprocal is ____________.
34. There
are 3 persons Sudhir, Arvind,
and Gauri. Sudhir lent cars
to Arvind and Gauri as many
as they had already. After some time Arvind gave as
many cars to Sudhir and Gauri
as many as they have. After sometime Gauri did the
same thing. At the end of this transaction each one of them had 24. Find the
cars each originally had.
35.A man bought a horse and a cart. If he
sold the horse at 10 % loss and the cart at 20 % gain, he would not lose
anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would
lose Rs. 10 in the bargain. The amount paid by him
was Rs._______ for the horse and Rs.________ for the cart.
Answers:
1.Answer:
30
days.
Explanation:
Before:
One day work= 1/20
One man’s one day work= 1
/ ( 20 * 75)
Now:
No.
Of workers= 50
One
day work= 50 * 1 /( 20 * 75)
The
total no. of days required to complete the work = (75 * 20) / 50 = 30
2.Answer:
0
%
Explanation:
Since 3x / 2= x / (2 / 3)
3.Answer:
5.3 %
Explanation:
He
sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then
he will gain (50 / 950) *100= 5.26
4.Answer:
250
lines of codes
5.Answer:
7
days
Explanation:
The
equation portraying the given problem is:
10 *x – 2 * (30 – x) =216 where
x is the number of working days.
Solving
this we get x = 23
Number
of days he was absent was 7 (30-23) days.
6.Answer:
150 men.
Explanation:
One
day’s work =2 / (7 * 90)
One
hour’s work =2 / (7 * 90 * 8)
One
man’s work =2 / (7 * 90 * 8 * 75)
The
remaining work (5/7) has to be completed within 60 days, because the total
number of days allotted for the project is 150 days.
So
we get the equation
(2 * 10 * x * 60) / (7 *
90 * 8 * 75)=5/7 where x is the number of men
working after the 90th day.
We get x = 225
Since we have 75 men already, it is
enough to add only 150 men.
7.Answer:
(c)
1
Explanation:
a percent of b : (a/100) * b
b percent
of a : (b/100) * a
a percent
of b divided by b percent of a : ((a / 100 )*b) /(b/100) * a )) = 1
8.Answer:
Cost
price of horse = Rs. 400 & the cost price of cart = 200.
Explanation:-
Let x be the cost price of the horse
and y be the cost price of the cart.
In the first sale there is no loss
or profit. (i.e.) The loss obtained is equal to the
gain.
Therefore(10/100) * x = (20/100)
* y
X=2 * y -----------------(1)
In the second sale, he lost Rs. 10. (i.e.) The loss is greater
than the profit by Rs. 10.
Therefore(5 / 100) * x = (5
/ 100) * y + 10 -------(2)
Substituting (1) in (2)
we get
(10 / 100) *
y =(5 / 100) * y + 10
(5 / 100) *
y =10
y = 200
From (1) 2 * 200
= x = 400
9.Answer:
3.
Explanation:
Since
inclusion of any male player will reject a female from the team. Since there
should be four member in the team and only three males
are available, the girl, n should included in the team always irrespective of
others selection.
10.Answer:
5
11.Answer:
1,2,3 & 4
12.Answer:
B
13.Answer:
11 & 9 apples per tree.
Explanation:
Let a, b, c, d & e be the total
number of apples bored per year in A, B, C, D & E ‘s
orchard. Given that a + 1 = b
+ 3 = c – 1 = d + 3 = e – 6
But the question
is to find the number of apples bored per tree in C and D ‘s
orchard. If is enough to consider c – 1 = d + 3.
Since the number of trees in C’s
orchard is 11 and that of D’s orchard is 13. Let x and y be the number of
apples bored per tree in C & d ‘s orchard
respectively.
Therefore 11 x – 1 = 13 y + 3
By trial and
error method, we get the value for x and y as 11 and 9
14.Answer:
G.
Explanation:
The order in which
they are climbing is R – G – K – H – J
15 – 18
Answer:
Novel
Name Author Publisher
Spy thriller Rathko Heron
Murder mysteryGorky Piegon
Gothic romanceBurchfieldBlueja
Science
fiction HopperSparrow
Explanation:
Given
Novel
Name Author Publisher
Spy thriller Rathko Heron
Murder
mysteryGorky Piegon
Gothic romanceBurchfieldBlueja
Science
fiction HopperSparrow
Since
Blueja doesn’t publish the novel by Burchfield and
Heron publishes the novel spy thriller, Piegon
publishes the novel by Burchfield.
Since
Hopper writes Gothic romance and Heron publishes the novel spy thriller, Blueja publishes the novel by Hopper.
Since
Heron publishes the novel spy thriller and Heron publishes the novel by
19.Answer:
451 times.
Explanation:
There
are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾) minutes = 45 minutes.
In
¾ of an hour there are (60 * 45) seconds = 2700 seconds.
Light flashed for every 6 seconds.
In
2700 seconds 2700/6 = 450 times.
The count start
after the first flash, the light will flashes 451 times in ¾ of an hour.
20.Answer:
(4)
Explanation:
P
A B
Since
p is a point on the line segment AB,
21.Answer: (c)
22.Answer: (b) & (d).
Ahmed
23 - 27.Answer:
Fakis Chandra
28.
Answer: Fakis
Explanation: Harsha Geetha
Eswar Balaji
Dhinesh
29.
Answer:
(5).
Explanation:
Since
every alternative letter starting from B of the English alphabet is written in
small letter, the letters written in small letter are b, d, f...
In the first two answers the letter
E is written in both small & capital letters, so they are not the correct answers.
But in third and fourth answers the letter is written in small letter instead
capital letter, so they are not the answers.
30.
Answer:
x
= 4
Explanation:
Since the side
of the square is x + 2, its perimeter = 4 (x + 2) = 4x + 8
Since the side of
the equilateral triangle is 2x, its perimeter = 3 * 2x = 6x
Also, the
perimeters of both are equal.
(i.e.) 4x + 8 = 6x
(i.e.) 2x = 8 è x = 4.
31. Answer:
(y – 2) / y.
Explanation:
To type a manuscript karthik took y hours.
Therefore his speed in typing = 1/y.
He was called away after 2 hours of
typing.
Therefore the work completed = 1/y *
2.
Therefore the remaining work to be
completed = 1 – 2/y.
(i.e.) work to be completed= (y-2)/y
32.Answer:
(2)
33.
Answer:
1
Explanation:
One
is the only number exists without reciprocal because the reciprocal of one is
one itself.
34.
Answer:
Sudhir had 39 cars, Arvind had 21
cars and Gauri had 12 cars.
Explanation:
Sudhir Arvind Gauri
Finally 24 24 24
Before Gauri’s
transaction 12 12 48
Before
Arvind’s transaction
6 42 24
Before
Sudhir’ s
transaction 39 21 12
35.Answer:
Cost
price of horse: Rs.
400 &
Cost
price of cart:Rs.
200
Explanation:
Let x
be the cost of horse & y be the cost of the cart.
10
% of loss in selling horse = 20 % of gain in selling the cart
Therefore(10 / 100) * x = (20 * 100) * y
è
x = 2y -----------(1)
5 % of loss in
selling the horse is 10 more than the 5 % gain in selling the cart.
Therefore (5 / 100) * x - 10 = (5 / 100) * y
è 5x - 1000= 5y
Substituting (1)
10y - 1000 =
5y
5y = 1000
y = 200
x = 400 from
(1)
Set 2 on series questions
For the following, find the next term in the series
1.6, 24, 60,120, 210
a) 336b) 366 c) 330 d) 660
Answer : a) 336
Explanation : The series is
1.2.3, 2.3.4, 3.4.5, 4.5.6, 5.6.7, ..... ( '.' means
product)
2.1, 5, 13, 25
Answer : 41
Explanation : The series is
of the form0^2+1^2, 1^2+2^2,...
3. 0, 5, 8, 17
Answer : 24
Explanation : 1^2-1, 2^2+1,
3^2-1, 4^2+1, 5^2-1
4. 1, 8, 9, 64, 25 (Hint : Every
successive terms are related)
Answer : 216
Explanation : 1^2, 2^3, 3^2,
4^3, 5^2, 6^3
5. 8,24,12,36,18,54
Answer : 27
6. 71,76,69,74,67,72
Answer : 67
7. 5,9,16,29,54
Answer : 103
Explanation : 5*2-1=9;
9*2-2=16; 16*2-3=29; 29*2-4=54; 54*2-5=103
8. 1,2,4,10,16,40,64
(Successive terms are related)
Answer : 200
Explanation : The series is
powers of 2 (2^0,2^1,..).
All digits are less than 8.Every second number is in octal number
system.
128 should follow 64. 128 base 10 =
200 base 8.
Exercise 2.2
Find the odd man out.
1. 3,5,7,12,13,17,19
Answer : 12
Explanation : All
but 12 are odd numbers
2. 2,5,10,17,26,37,50,64
Answer : 64
Explanation : 2+3=5; 5+5=10;
10+7=17; 17+9=26; 26+11=37; 37+13=50; 50+15=65;
3. 105,85,60,30,0,-45,-90
Answer : 0
Explanation :
105-20=85; 85-25=60; 60-30=30; 30-35=-5; -5-40=-45; -45-45=-90;
Exercise 3
Solve the following.
1. What is the number of zeros at
the end of the product of the numbers from 1 to 100?
Answer : 127
2. A fast typist can type some
matter in 2 hours and a slow typist can type the same in 3 hours. If both type combinely, in how much time will they finish?
Answer : 1 hr 12 min
Explanation :
The fast typist's work done in 1 hr = 1/2
The slow typist's work done in 1 hr
= 1/3
If they work combinely,
work done in 1 hr = 1/2+1/3 = 5/6
So, the work
will be completed in 6/5 hours. i.e., 1+1/5 hours = 1hr 12 min
3. Gavaskar's
average in his first 50 innings was 50. After the 51st innings, his average was
51. How many runs did he score in his 51st innings. (supposing that he lost his wicket in his 51st innings)
Answer : 101
Explanation : Total
score after 50 innings = 50*50 = 2500
Total
score after 51 innings = 51*51 = 2601
So,
runs made in the 51st innings = 2601-2500 = 101
If
he had not lost his wicket in his 51st innings, he would have scored an
unbeaten 50 in his 51st innings.
4. Out of 80 coins, one is
counterfeit. What is the minimum number of weighings
needed to find out the counterfeit coin?
Answer : 4
5. What can you conclude from the
statement : All green are blue, all blue are red. ?
(i)
some blue are green
(ii)
some red are green
(iii)
some green are not red
(iv)
all red are blue
(a)
i or ii but not both
(b)
i & ii only
(c)
iii or iv but not both
(d)
iii & iv
Answer : (b)
6. A rectangular plate with length
8 inches, breadth 11 inches and thickness 2 inches is available. What is the
length of the circular rod with diameter 8 inches and equal to the volume of
the rectangular plate?
Answer : 3.5 inches
Explanation : Volume of the circular rod (cylinder) =
Volume of the rectangular plate
(22/7)*4*4*h
= 8*11*2
h
= 7/2 = 3.5
7. What is the sum of all numbers
between 100 and 1000 which are divisible by 14 ?
Answer : 35392
Explanation : The number closest to 100 which is greater
than 100 and divisible by 14 is 112,
which is the first term of the series which has to be summed.
The number closest to 1000 which is
less than 1000 and divisible by 14 is 994, which is the last term of the
series.
112
+ 126 + .... + 994 = 14(8+9+ ... + 71) = 35392
8. If s(a)
denotes square root of a, find the value of s(12+s(12+s(12+ ......upto
infinity.
Answer : 4
Explanation : Let x = s(12+s(12+s(12+.....
We can writex = s(12+x). i.e., x^2 = 12 + x.
Solving this quadratic equation, we get x = -3 or x=4. Sum cannot be -ve and hence sum = 4.
9. A cylindrical container has a
radius of eight inches with a height of three inches. Compute how many inches
should be added to either the radius or height to give the same increase in
volume?
Answer : 16/3 inches
Explanation : Let x be the amount of increase. The
volume will increase by the same amount if the radius increased or the height
is increased.
So, the effect
on increasing height is equal to the effect on increasing the radius.
i.e.,
(22/7)*8*8*(3+x) = (22/7)*(8+x)*(8+x)*3
Solving
the quadratic equation we get the x = 0 or 16/3. The possible increase would be
by 16/3 inches.
10. With just six weights and a
balance scale, you can weigh any unit number of kgs
from 1 to 364. What could be the six weights?
Answer : 1, 3, 9, 27, 81, 243 (All powers of 3)
11. Diophantus
passed one sixth of his life in childhood, one twelfth in youth, and one
seventh more as a bachelor; five years after his marriage a son was born who
died four years before his father at half his final age. How old is Diophantus?
Answer : 84 years
Explanation : x/6 + x/12 + x/7 + 5 + x/2 + 4 = x
12 . If
time at this moment is 9 P.M., what will be the time 23999999992 hours later?
Answer : 1 P.M.
Explanation : 24 billion hours later, it would be 9 P.M.
and 8 hours before that it would be 1 P.M.
13. How big will an angle of one
and a half degree look through a glass that magnifies things three times?
Answer : 1 1/2 degrees
Explanation : The magnifying glass cannot increase the
magnitude of an angle.
14. Divide 45 into four parts
such that when 2 is added to the first part, 2 is subtracted from the second
part, 2 is multiplied by the third part and the fourth part is divided by two,
all result in the same number.
Answer:
8, 12, 5, 20
Explanation:
a + b + c + d =45;a+2 = b-2 = 2c
= d/2; a=b-4; c = (b-2)/2; d = 2(b-2);b-4 + b + (b-2)/2 + 2(b-2) = 45;
15. I drove 60 km at 30 kmph and then an additional 60 km at 50 kmph.
Compute my average speed over my 120 km.
Answer : 37 1/2
Explanation : Time reqd for
the first 60 km = 120 min.; Time reqd for the second
60 km = 72 min.; Total time reqd = 192 min
Avg speed = (60*120)/192 = 37 1/2
Questions 16 and 17 are based on the following :
Five executives of European Corporation
hold a Conference in Rome
Mr. A converses in Spanish & Italian
Mr. B, a spaniard, knows English also
Mr. C knows English and belongs to
Mr. D converses in French and Spanish
Mr. E , a native
of
16. Which of the following can act as
interpreter if Mr. C & Mr. D wish to converse
a) only Mr. Ab) Only Mr. B c)
Mr. A & Mr. Bd) Any of the
other three
Answer : d) Any of the other three.
Explanation :From the data given, we can infer the following.
A
knows Spanish, Italian
B knows Spanish,
English
C knows Italian,
English
D knows Spanish,
French
E knows Italian, French
To act as an
interpreter between C and D, a person has to know one of the combinations Italian&Spanish, Italian&French,
English&Spanish,English&French
A, B, and E know atleast one of the
combinations.
17. If a 6th executive is brought
in, to be understood by maximum number of original five he should be fluent in
a) English & French b)
Italian & Spanish c) English
& French d) French & Italian
Answer : b)
Italian & Spanish
Explanation : No of executives who know
i) English is 2
ii) Spanish is 3
iii) Italian is 3
iv) French is 2
Italian &
Spanish are spoken by the maximum no of executives. So, if the 6th executive is
fluent in Italian & Spanish, he can communicate with all the original five
because everybody knows either Spanish or Italian.
Answer : 625
Explanation : The sum of the first n natural odd nos is square(n).
1+3 = 4 = square(2) 1+3+5 = 9 = square(3)
a)
2 b) 7c) 3d) 11
Exercise Set 3 puzzle questions
Try the following.
S : The
difference between R's age and mine is three years.
J : R is the
youngest.
R : Either I am
24 years old or J 25 or S 26.
J : All are
above 24 years of age.
S : I am the
eldest if and only if R is not the youngest.
R : S is elder
to me.
J : I am the eldest.
R : S is not 27
years old.
S : The sum of
my age and J's is two more than twice R's age.
One of the three
had been telling a lie throughout whereas others had spoken the truth.
Determine the ages of S,J,R.
1, 2, 4, 10, 16,
40, 64,
Questions 9-12 are based on the following :
Three adults –
Roberto, Sarah and Vicky – will be traveling in a van with five children –
Freddy, Hillary, Jonathan, Lupe, and Marta. The van has a driver’s seat and one
passenger seat in the front, and two benches behind the front seats, one beach
behind the other. Each bench has room for exactly three people. Everyone must
sit in a seat or on a bench, and seating is subject to the following
restrictions: An adult must sit on each bench.
Either Roberto or Sarah must sit in the
driver’s seat.
Jonathan must sit immediately beside Marta.
(a) Jonathan (b) Lupe(c)
Roberto (d) Sarah(e) Vicky
10.Which of the following groups of three can
sit together on a bench?
(a) Freddy,
Jonathan and Marta(b) Freddy,
Jonathan and Vicky
(c) Freddy,
Sarah and Vicky (d)
Hillary, Lupe and Sarah
(e) Lupe, Marta
and Roberto
(a) 6K (b) 8K (c) 12K(d)
7K
(I) z2
= 25
(II) w = 9
To answer the
question,
a) Either I or
II is sufficient
b) Both I and
II are sufficient but neither of them is alone sufficient
c) I & II
are sufficient
d) Both are not
sufficient